Question

if sin A = square root 3/2 and cos B=root 3/2 find the value of tanA - tan B / 1+tanAtanB

Answer 1

Given sin a = square root 3/2 then cos a = 1/2

          cos b = root 3/2 then sin b = 1/2

          Tan a = sin a/cosa 

                    = root 3

         tan b = sin b/cos b

                  = 1/root 3

        tan a - tan b / 1+tan a tanb = 1/root 3.


Hope this helps!

Answer 2

30 and 60
a and b
may be the answer is correct