Math, asked by abc147, 1 year ago

if sin A = square root 3/2 and cos B=root 3/2 find the value of tanA - tan B / 1+tanAtanB

Answers

Answered by siddhartharao77
23
Given sin a = square root 3/2 then cos a = 1/2

          cos b = root 3/2 then sin b = 1/2

          Tan a = sin a/cosa 

                    = root 3

         tan b = sin b/cos b

                  = 1/root 3

        tan a - tan b / 1+tan a tanb = 1/root 3.


Hope this helps!
Answered by chinaa3
8
30 and 60
a and b
may be the answer is correct
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