if sin A = square root 3/2 and cos B=root 3/2 find the value of tanA - tan B / 1+tanAtanB
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Given sin a = square root 3/2 then cos a = 1/2
cos b = root 3/2 then sin b = 1/2
Tan a = sin a/cosa
= root 3
tan b = sin b/cos b
= 1/root 3
tan a - tan b / 1+tan a tanb = 1/root 3.
Hope this helps!
cos b = root 3/2 then sin b = 1/2
Tan a = sin a/cosa
= root 3
tan b = sin b/cos b
= 1/root 3
tan a - tan b / 1+tan a tanb = 1/root 3.
Hope this helps!
Answered by
8
30 and 60
a and b
may be the answer is correct
a and b
may be the answer is correct
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