Question

if sin alpha =1/3 evaluate tan alpha.sec alpha cos alpha.cosec alpha

Answer 1

hey

here is your answer

hope its help you

Answer 2

Sin alpha = 1/3

(Tan alpha. Sec alpha) (Cos alpha.Cosec alpha)

= (sin alpha/cos^2 alpha)(Cos alpha/ sin alpha)

= 1 / Cos alpha

Now Sin alpha = 1 / 3 = P / H

Find B using Pythagoras theorem

B^2 = H^2 - P^2

B^2 = 3^2 + 1^2 = 10

$b = \sqrt{10}$

Now Cos alpha = B / H


$= \sqrt{10} \div 1 = \sqrt{10}$
On putting value in 1 / Cos alpha we get


$= 1 \div \sqrt{10}$


Thanks