Question

if sin alpha + beta is equal to 1 then what is the value of cos alpha minus beta​

Answer 1

The value of $\cos(\alpha - \beta)\  is ""<strong>[tex]\dfrac{\sqrt{3} }{2}$".

Step-by-step explanation:

We have,$\sin(\alpha +\beta)\ = 1)$\

⇒$\sin(\alpha +\beta)\ = \sin(90\degree)$\

∴ α + β = 90°

Let α = 60° and β = 30°

∴$\cos(\alpha - \beta)\ = \cos(60\degree - 30\degree)$

⇒ $</strong>\cos(\alpha - \beta)\ = \cos(30\degree)\ <strong>=\dfrac{\sqrt{3} }{2}$

Hence, the value of $\cos(\alpha - \beta)\  is "<strong>[tex]\dfrac{\sqrt{3} }{2}$".

Answer 2

Answer:answer is sin 2 beeta

Step-by-step explanation:

In the attachment