Math, asked by eshant7061, 8 months ago

If sin alpha =root 3 by 2 cos beta =0 find the value of beta -alpha

Answers

Answered by shruthimurthy
0

Answer:

30

Step-by-step explanation:

sin alpha=root 3 by 2

alpha=sin^-1 of root 3 by 2

alpha =60

cos beta=0

beta=cos^-1 of0

beta =90

beta - alpha

=90-60

=30

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