Question

If sin B = cos(2B - 30) where 2B is an acute angle therefore the value of B = ___

Give your answer with an example

Answer 1

Answer:

40

Step-by-step explanation:

$cos(90 - b) = cos(2b - 30)$

$90 - b = 2b - 30$

$120 = 3b$

$b = 40$

Answer 2

Answer:

$your \: ans \\ hope \:it \: help \: yoy$

Step-by-step explanation:

$\sin(b) = \cos(2b - 30) \\ = > \sin(b) = \sin({90 - 2b + 30}) \\ = > b = 90 - 2b + 30 \\ = > 3b = 120 \\ = > b = \frac{120}{3} \\ = > b = 40 \\ \\ \sin(0) = 0 \\ \cos(0) = 1 \\ \tan(0) = 0 \\ \sin(30) = \frac{1}{2} \\ \cos(30) = \frac{ \sqrt{3} }{2} \\ \tan(30) = \frac{1}{ \sqrt{3} } \\ \sin(45) = \frac{1}{ \sqrt{2} } \\ \cos(45) = \frac{1}{ \sqrt{2} } \\ \tan(45) = 1 \\ \sin(60) = \frac{ \sqrt{3} }{2} \\ \cos(60) = \frac{1}{2} \\ \tan(60) = \sqrt{3} \\ \sin(90) = 1 \\ \cos(90) = 0 \\ \tan(90) = \infty$

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