Question

If sinθ−cosθ=0 (0°≤θ≤90°) and secθ+cosec θ=x , then find x .

Answer 1

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Answer 2

Answer:

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Step-by-step explanation:

 sinθ – cosθ =0

sinθ = cosθ

1/cosecθ = 1/secθ

cosecθ=secθ

sec(90 – θ)=secθ

90 – θ=θ

2θ=90

θ=45

Therefore,  

secθ + cosecθ

=sec45 +cosec45

= √2+√2

= 2√2   {x=2√2}

                             [Ans]

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