If sinθ−cosθ=0, then Find the value of (sinθ+cosθ).
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Answer:
If sinx-cosx=0,then sinx=cosx, which is possible at x= pi/4 or 5(pi/4)
implying that sinx+cosx=sqrt(2) or -sqrt(2) if x is in the first and third quadrant respectively.
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Answer:
The value of (sinθ+cosθ) =√2
Step-by-step explanation:
sinθ−cosθ=0
⇒sinθ=cosθ
⇒tanθ=1
⇒θ=45°
∴sinθ+cosθ=
=sin45°−cos45°
=1/√2+1/√2
=2/√2
=√2
Hence, the answer is √2
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