If sinθ = cos (θ - 45), where θ is acute, find the value of θ.
Answers
Answered by
2
sinØ = cos (Ø-45)
since sinØ = cos(90-Ø)
therefore Cos (90-Ø) = cos(Ø-45)
90-Ø = Ø-45
90 + 45=Ø + Ø
135 = 2Ø
Ø= 62.5°
since sinØ = cos(90-Ø)
therefore Cos (90-Ø) = cos(Ø-45)
90-Ø = Ø-45
90 + 45=Ø + Ø
135 = 2Ø
Ø= 62.5°
Answered by
0
Answer:
67.5
Step-by-step explanation:
cos(90-sinθ)=cos(θ-45)
90-θ=θ-45
90+45=2θ
135/2=θ
θ=67.5
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