If sin θ = cos θ and 0° < θ <90°, then find the values of sin θ and cos θ.
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Answered by
2
Step-by-step explanation:
The only value of theta that satisfies here is 45° because sin45°=Cos45°=1√2.
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Answered by
4
sin θ = cos θ
sin θ/cos θ = 1
tan θ = 1
tan 45° = tan θ
θ = 45°
then ,
- sin θ = sin 45° = ½
- cos θ = cos 45° = 1/√2
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