If Sin + Cos = p and Sec + Cosec = q , show that q ( p 2 – 1) = 2 p.
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Solution
→ p = sin∅ + cos∅
→ p² = (sin∅ + cos∅)²
→ p² = sin²∅ + cos² + 2 sin∅ cos∅
→ p² = 1 + 2 sin∅ cos∅
→ p² - 1 = 2 sin∅ cos∅
→ q = sec∅ + cosec∅
→ q = 1/cos∅ + 1/sin∅
→ q = (sin∅ + cos∅)/cos∅ sin∅
→ q(p² - 1) = (sin∅ + cos∅)/cos∅ sin∅ × 2 sin∅ cos∅
→ 2 (sin∅ + cos∅) → 2p
Q.E.D
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