if sinθ = cosθ , then find the value of 2tan^2θ + sin^2θ -1
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ANSWER:
=2-cos²Θ
Step-by-step explanation:
2tan²Θ = 2(sin²Θ/cos²Θ)
since sinΘ=cosΘ
sin²Θ=cos²Θ
∴2tan²Θ=2(cos²Θ/cos²Θ)
=2(1)=2
sin²Θ-1=(-cos²Θ) [sin²Θ+cos²Θ=1]
∴2tan²Θ+sin²Θ-1= 2-cos²Θ
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