Math, asked by RuchirRaina, 9 months ago

if sinθ = cosθ , then find the value of 2tan^2θ + sin^2θ -1​

Answers

Answered by santhasekar1977
1

ANSWER:

         =2-cos²Θ

Step-by-step explanation:

2tan²Θ = 2(sin²Θ/cos²Θ)

since sinΘ=cosΘ

        sin²Θ=cos²Θ

∴2tan²Θ=2(cos²Θ/cos²Θ)

             =2(1)=2

sin²Θ-1=(-cos²Θ)       [sin²Θ+cos²Θ=1]

∴2tan²Θ+sin²Θ-1= 2-cos²Θ

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