If sin + cosec=2 find the value of cos^2-cot^2
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Solution :
Given sinA + cosecA = 2---(1)
Do the square both sides
of equation (1) , we get
(sinA + cosecA)² = 2²
=> sin²A + cosec²A +2sinAcosecA = 4
=> 1 - cos²A + 1 + cot²A + 2 = 4
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[ Since , i )sin²A = 1 - cos²A
ii ) cosec²A = 1 + cot²A
iii ) sinAcosecA = 1
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=> 4 - 4 = cos²A - cot²A
=> 0 = cos²A - cot²A
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