Question

if Sin Q - Root 3 cos Q = 0, 0<Q<90°​

Answer 1

Step-by-step explanation:

We have,

3

sinθ−cosθ=0

3

sinθ=cosθ

3

=

sinθ

cosθ

3

=cotθ

tanθ=

3

1

tanθ=tan

6

π

θ=nπ+

6

π

where n ε Z

Hence, this is the answer.