if sinθ+sin2θ=1 then cos2θ+cos4θ is equal to
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Answered by
2
sinθ+sin2θ=1
cos2θ+cos4θ = 0
hope helps
cos2θ+cos4θ = 0
hope helps
Answered by
4
at theta = π/2
equation 1st satisfying
so Value
=> Cos2(π/2) + Cos4(π/2)
= Cosπ + Cos2π
= -1 + 1
= 0
equation 1st satisfying
so Value
=> Cos2(π/2) + Cos4(π/2)
= Cosπ + Cos2π
= -1 + 1
= 0
mohammaddalwai:
How is cosn=-1
It’s correct
?????
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