if sin square A is equal to 2 sin a then find the value of a
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Hey mate, here's your answer,
![sin {}^{2}a = 2sina \\ sina = 0 \\ \sin(a) = 2(not \: possible) \\ ( \\ but \: i \: think \: the \: question \: is \\ \sin ^{2}a = sin2a \\ for \: this \: case \\ sin \: a \times sin \: a = 2sin \: a \: cos \: a \\ sina = 0 \\ therefore \: a = 0 \\ or \\ sin \: a = 2cos \: a \\ tan \: a = 2 \\ therefore \\ a = {tan}^{ - 1} 2 sin {}^{2}a = 2sina \\ sina = 0 \\ \sin(a) = 2(not \: possible) \\ ( \\ but \: i \: think \: the \: question \: is \\ \sin ^{2}a = sin2a \\ for \: this \: case \\ sin \: a \times sin \: a = 2sin \: a \: cos \: a \\ sina = 0 \\ therefore \: a = 0 \\ or \\ sin \: a = 2cos \: a \\ tan \: a = 2 \\ therefore \\ a = {tan}^{ - 1} 2](https://tex.z-dn.net/?f=sin+%7B%7D%5E%7B2%7Da+%3D+2sina+%5C%5C+sina+%3D+0+%5C%5C++%5Csin%28a%29+%3D+2%28not+%5C%3A+possible%29+%5C%5C+%28+%5C%5C+but+%5C%3A+i+%5C%3A+think+%5C%3A+the+%5C%3A+question+%5C%3A+is+%5C%5C++%5Csin+%5E%7B2%7Da+%3D+sin2a+%5C%5C+for+%5C%3A+this+%5C%3A+case+%5C%5C+sin+%5C%3A+a+%5Ctimes+sin+%5C%3A+a+%3D+2sin+%5C%3A+a+%5C%3A+cos+%5C%3A+a+%5C%5C+sina+%3D+0+%5C%5C+therefore+%5C%3A+a+%3D+0+%5C%5C+or+%5C%5C+sin+%5C%3A+a+%3D+2cos+%5C%3A+a+%5C%5C+tan+%5C%3A+a+%3D+2+%5C%5C+therefore+%5C%5C+a+%3D++%7Btan%7D%5E%7B+-+1%7D+2)
hope it helps you, pls mark me as the brainliest....
hope it helps you, pls mark me as the brainliest....
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