If Sin theta = 2mn/(m^2 + n^2), then show that: (Sin theta * Cot theta)/Cos theta = 1...
plz answer fast...
Answers
Answered by
22
sinx=2mn/(m^2+n^2)
(sinx*cotx)/cosx=1
LHS
(sinx*cosx/sinx)cosx
= 1
shubhnamdeepkaursand:
Thanks..but thats not what the ans is...I have seen at a no. of websites but they are saying that (Sin theta*Cot theta)/Cos theta is always one..but let me think..why have they given the value of sin???...l'm confused..
Answered by
43
Answer:
Step-by-step explanation:
Attachments:
Similar questions