Question

If sin theta = 3/5, then prove that (tan theta+sec theta)^2 = 4

Answer 1

Answer:

sinθ=3/5

P/H=3/5

ACC TO PYTHA THM,

H²-P²=B²

5²-3²=B²

25-9=B²

16=B²

4=B              cos=4/5(B/H)

(tanθ+secθ)²

(sinθ/cosθ +1/cosθ)²

(sin+1/cos)²

(sin+1)²/cos²

(3/5 +1)²/(4/5)²

(8/5)²/16/25

64/25*25/16

64/16

4= RHS

PROVED:)

Step-by-step explanation:

Answer 2

Answer:

4=4

LHS=RHS

Step-by-step explanation:

WKT 3,5,4is a puthogorun triplets

so AB=4

(tan∅+ sec∅)² =4

(sin∅/cos∅+1/cos∅)²

sin∅+1/cos∅)²

(3/5+1/4/5)²

(3+5/5/4/5)²

(8/4)²

(64/16)

4=4

LHS = RHS

hope it helps