if sin theta =4/5 then find cot theta
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sin Ф = 4/5
from figure, sin Ф =AB/AC
Let BC = x
According to Pythagoras theorem,
AC² = AB² + BC²
5² = 4² + x²
25 = 16 + x²
25 - 16 = x²
9 = x²
(Taking under square root on both sides)
∴ x = 3
∴ Cot Ф = BC / AB = 3/4.
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