Question

if sin theta = 4/5 then find the value of 3sec theta _ 5 cos theta ​

Answer 1

Answer:

2

Step-by-step explanation:

sin θ= 4/5

sin²θ+cos²θ=1

cos θ= √(1-sin²θ)

cos θ= √(1-(4/5)²)

        = √(1- 16/25)  

        = √(9/25)

        = 3/5

sec θ = 1/cos θ

sec θ= 5/3

3sec θ- 5cosθ = 3*5/3 - 5*3/5

                       = 5-3

                       = 2