if sin theta =4/5 then find the value of 4tan theta - 5cos theta /sec theta +cot theta
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=sin theta=4/5=p/h
b^2=h^2-p^2
=5^2-4^2
=25-16
=9
b=√9=3
4tan theta -5 cos theta/sec theta+ cot theta
=4*p/b-5*b/h/h/b+b/p
=4*4/3-5*3/5/5/3+3/4
=80/15-45/15/20/12+9/12
(15&12 r lcm)
=35/15*12/29
=28/29
b^2=h^2-p^2
=5^2-4^2
=25-16
=9
b=√9=3
4tan theta -5 cos theta/sec theta+ cot theta
=4*p/b-5*b/h/h/b+b/p
=4*4/3-5*3/5/5/3+3/4
=80/15-45/15/20/12+9/12
(15&12 r lcm)
=35/15*12/29
=28/29
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