if sin theta =5/13.then find cos theta
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sin theeta = 5 / 13
=> P / H = 5 / 13
P = 5 ; H = 13
by Pythagoras Theorem
B² = H² - P²
= (13)² - (5)²
= 169 - 25
= 144
B = √144
B = 12
:- cos theeta = B / H
= 12 / 13
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