Question

When the diameter of shaft is doubled its torque transmitting capacity will increase by?

Answer 1

Answer :- When the diameter of shaft is doubled its torque transmitting capacity will increase by

Answer 2

Answer:

Diameter of shaft is doubled its torque.

Explanation:

$P$=$2$π$NT$/$60$

$P$ is directly proportional to T and $T$ is directly proportional to $d^{3}$

Therefore,

$\frac{P_{2} }{P_{1} } = (\frac{d_{2} }{d_{1} } )^{3} \\ =(\frac{2d_{1} }{d_{1} } )^{3}$

$P_{2} =8P_{1}$

Hence,

It is eight times.