Question

If sin theta =6/10, then find sin^2 theta + cos^ theta

Answer 1

Answer:

1

Step-by-step explanation:

Given: sin θ = 6/10

Solution:

sin θ = angle opposite to θ = 6/10

hyptoenuese

By pythagoras theorem,

(hypotenuese)² = (base)² + (perpendicular)²

(10)² = (CB)² + (6)²

(CB)² = 100 - 36

= 64

CB = 8

cos θ = side adjacent to angle θ = 8/10

hyptoenuese

sin ² θ + cos ² θ

= (6/10)² + (8/10)²

= 36/100 + 64/100

= 100/100

=1