Question

if sin theta =60/61 then find cos theta and tan theta ​

Answer 1

Step-by-step explanation:

cos trita=11/61

tan trita=60/11

Answer 2

Answer:

tan(θ)= 60/11

cos(θ)=11/61

Step-by-step explanation:

$\sin(θ) = \frac{60}{61} \\ \sin^{2}(θ) + \ \cos^{2}(θ) = 1 \\ ( \frac{60}{61} ) {}^{2} + \cos^{2}(θ) = 1 \\ \frac{3600}{3721} + cos^{2}(θ) = 1 \\ cos^{2}(θ) = 1 - \frac{3600}{3721} = \frac{121}{3721} = \frac{(11)^{2}}{61 {}^{2} } \\ \cos(θ) = \frac{11}{61} \\ \tan(θ) = \frac{sin(θ)}{cos(θ)} \\ = \frac{ \frac{60}{61} }{ \frac{11}{61} } \\ = \frac{60}{11}$