Question

if sin theta =a/b then find the value of cos theta in the form of a and b

Answer 1

Hey mate ☺️

If sin theta =a/b

Then, sinθ=a/b

∴, cosθ=√(1-sin²θ) [∵, sin²θ+cos²θ=1]

or, cosθ=√(1-a²/b²)

or, cosθ=√{(b²-a²)/b²}

or, cosθ=√(b²-a²)/b

Hope it helps you ☺️✌️✌️

Answer 2

HOLA

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$sin \: = \: \frac{p}{h} \: = \: \frac{a}{b} \\ \\ by \: pythagoras \: theoreum \: we \: have \\ \\ ac {}^{2} \: = \: ab {}^{2} \: + \: bc {}^{2} \\ \\ bc {}^{2} \: = \: ab {}^{2} \: - \: ac {}^{2} \\ \\ bc {}^{2} = \: a {}^{2} \: + \: b {}^{2} \\ \\ bc \: = \: \sqrt{a {}^{2} \: + \: b {}^{2} } = \: a \: + \: b \\ \\ \\ so \: \: \: \: cos \: = \: \frac{b}{h} \: = \: \frac{a \: + \: b}{b}$
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HOPE U UNDERSTAND ❤❤❤