Question

If * sin theta = a/(sqrt(a ^ 2 + b ^ 2)) b sin theta = a cos theta ​

Answer 1

Answer:

Instead of theta we shall take A

SinA + cosA = 1/√2

The coefficients of sinA and cosA are 1,1.

So multiply all the terms with

1/√(1^2+1^2 = 1/√2

1/√2 sinA + 1/√2 cosA = 1/2 =>

sinA.cos π/4 + cosA.sinπ/4 = sin π/6

=> sin(A+ π/4) = sin π/6

So. A+ π/4 = π/6 (here we have not taken the general solution)

A = π/6 - π/4 = -π/12

So 4A = -π/3 => tan 4A = tan(-π/3)

= -tan π/3 = -√3