if sin theta = b/a what is the value of cos theta
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sinθ = b/a = Perpendicular / Hypotenuse
Using Pythagoras Theorem,
Base = a^2 - b^2
cos θ = (a^2 - b^2) / a
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Answer:
let theta be x
sinx=b/a
sinx=opposite side/hypotenuse side
by pythagorous theorem,
AC²=AB²+BC²
a²=b²+BC²
BC²=a²-b²
BC=√a²-b²
cosx=adjacent side/hypotenuse side
cosx=√a²-b²/a
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