If sin theta + cos theta = √2, and b= √2(sin theta + cos theta)/ sin theta × cos theta. find 'b'
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given sin theta + cos theta is root 2
so putting that value in the question
(sin theta + cos theta ) *( sin theta + cos theta)/sin theta * cos theta
so
sin2theta + cos2 theta /sin theta * cos theta
ie:
1/sin theta* cos theta
= cosec theta * cos theta
therefore the value of b is cosec theta * cos theta
meaning of symbols i have used
*= multiply
sin2 theta = sin square theta
/= division
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