Question

if sin theta +cos theta =√2 ,then evaluate tan theta +cot theta

Answer 1

ans 2 h full explanations photo me show

Answer 2

Answer:

Step-by-step explanation:

sin θ + cos θ = √2

⇒ (sin θ + cos θ)^2 =  (√2)^2

⇒ sin^2θ + cos^2θ + 2sin θcosθ = 2

⇒ 1 + 2 sin θ cos θ = 2

⇒ sin θ cos θ = 1/2 ..... (i)

we know,

sin^2 θ + cos^2 θ = 1 ...(ii)

Dividing (ii) by (i) we get

sin^2θ + cos^2θ ÷ sinθcosθ = 1 ÷ 1/2

⇒ tan θ + cot θ = 2