if sin theta + cos theta 2 then find tan theta + cot theta
Sakshi15403:
your question is wrong...
u mean sin theta + cos theta =2 , right?
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sin + cos = 2 (given)
=> sin = 2- cos
(tan= sin/ cos and cot = cos/ sin, lcm = sin×cos
tan + cot = (sin*sin + cot*cot) / sin×cot )
sin sq + cos sq = 1 and so tan + cot = 1/sin×cot
=> 1 / (2- cos)(cos)
=> your answer is 1/(2cos-cos sq)
=> sin = 2- cos
(tan= sin/ cos and cot = cos/ sin, lcm = sin×cos
tan + cot = (sin*sin + cot*cot) / sin×cot )
sin sq + cos sq = 1 and so tan + cot = 1/sin×cot
=> 1 / (2- cos)(cos)
=> your answer is 1/(2cos-cos sq)
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