Question

if sin theta-cos theta=3/5, then, Find the value of (Sin 0.Cos 0))


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Answer 1

Answer:

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ΔABC be a right angled at B

Let ∠ACB=θ

Given that, sin θ = 3/5

AB/AC = 3/5

Let AB = 3x

then AC = 5x

In right angled ΔABC,

By Pythagoras theorem,

We get

(5x)

2

=(3x)

2

+BC

2

BC

2

=(5x)

2

−(3x)

2

BC

2

=(2x)

2

BC=4x

(i) cos θ = Base/ Hypotenuse

= BC / AC

= 4x /5x

= 4/5

(ii) tan θ = perpendicular/Base

= AB/BC

= 3x/4x

=3/4