if sin theta =cos theta find 3 tan^2 theta + 2 sin^2 theta - 1
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sin x = cos x
tan x = 1
x = 45 degrees
sin x = 1/√2
3 tan^2 x + 2 sin^2x - 1 = 3 (1) + 2 (1/2) - 1 = 3 + 1 - 1 = 3
tan x = 1
x = 45 degrees
sin x = 1/√2
3 tan^2 x + 2 sin^2x - 1 = 3 (1) + 2 (1/2) - 1 = 3 + 1 - 1 = 3
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