Question

If sin theta = cos theta find the value of cot^2 theta +tan theta sec theta + 1

Answer 1

Solution

The value of the above equation is 2 + √2

Given

sin∅ = cos∅

If ∅ lies in the first quadrant,then sine and cosine graphs meet at π/4

➠ sin∅/cos∅ = 1

➠ tan ∅ = tan π/4

➠ ∅ = π/4

Now,

cot²π/4 + tan π/4 sec π/4 + 1

➠ (1)² + 1 × √2 + 1

➠ 1 + 1 + √2

➠ 2 + √2

Answer 2

Hey

Here's your answer !!!

According to the given Question,we can write it also as

tan∅ = 1

→ ∅ = 45°

Now,

cot²45 + tan45 sec45 + 1

1² + 1×√2 + 1

2 + √2

Hope it helps

TGA