If sin theta + cos theta is equal to root 3 then prove that tan theta + cot theta is equal to 1
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Step-by-step explanation:
Sinθ + Cosθ = √ 3
Squaring both the sides,
=> (Sinθ + Cosθ)^2 = (√ 3)^2
=> (Sinθ)^2 + (Cosθ)^2 + 2SinθCosθ = 3
=> Sin^2θ + Cos^2θ + 2sinθcosθ = 3
=> 1 + 2SinθCosθ = 3
=> 2SinθCosθ = 2
=> SinθCosθ = 1 ......(i)
Now,
tanθ + cotθ
= Sinθ/Cosθ + Cosθ/Sinθ
= Sin^2θ + Cos^2θ/SinθCosθ
= 1/SinθCosθ
= 1/1 (from(i))
= 1
Hence, proved....
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