Question

if sin theta + cos theta is route two then evaluate tan
theta + cot theta

Answer 1

where theta =0
sin0 +cos0=root 2
on squaring both side we get
sin^2 0+cos^2 0 +2sin 0 cos 0 =2
1+2sin0 cos 0=2
2sin 0 cos 0=1
sin 0 cos 0 =1/2
Now we have
tan0 +cot 0
sin 0/cos 0 +cos 0/sin 0
(sin^2 0+cos^2 0)/sin 0 cos 0
1×1/sin 0 cos 0
1×2
2