Question

if sin theta + cos theta=p;tan theta+cot theta=q then find q×(p square-1)

​

Answer 1

Answer:

Step-by-step explanation:

here, p= sin theta + cos theta

         q=tan theta + cot theta

q x( p square -1)

= tan theta + cot theta x( (sin theta + cos theta)^2 - 1)

= tan theta + cot theta x( sin^2 + cos^2 + 2 cos theta x sin theta -1) {(a + b)^2}

= tan theta + cot theta x( 1-1 + 2 cos theta x sin theta )

= sin theta/ cos theta + cos theta/ sin theta x ( 2 cos theta sin theta )

= sin^2 theta + cos^2 theta / sin theta cos theta x ( 2 cos theta sin theta )

=1 x 2 = 2 ( the denominator sin theta cos theta divides 2 sin theta cos theta)

Hope i was able to help you!