if sin theta + cos theta = root 2 then find tan theta + cot theta
AshuAbhishek1:
the required answer is 2
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as it is given that sinx + cosx= √2
now squaring both the sides you will get
sin^2x + cos^2x + 2sinxcosx=2
1+2sinxcosx=2
sinx cosx=1/2
now the question that is to find the value of tanx + cotx
first convert them into sin and cos
after converting them the numerator will be equal to 1 and denominator will be sinx cosx
which is equal to 1/2
therefore the answer will be 2
now squaring both the sides you will get
sin^2x + cos^2x + 2sinxcosx=2
1+2sinxcosx=2
sinx cosx=1/2
now the question that is to find the value of tanx + cotx
first convert them into sin and cos
after converting them the numerator will be equal to 1 and denominator will be sinx cosx
which is equal to 1/2
therefore the answer will be 2
Answered by
0
Answer:
as it is given that sinx + cosx= √2
now squaring both the sides you will get
sin^2x + cos^2x + 2sinxcosx=2
1+2sinxcosx=2
sinx cosx=1/2
now the question that is to find the value of tanx + cotx
first convert them into sin and cos
after converting them the numerator will be equal to 1 and denominator will be sinx cosx
which is equal to 1/2
therefore the answer will be 2
Step-by-step explanation:
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