If sin theta +cos theta= root 3 then prove thattan theta +cot theta =1
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sinФ+cosФ=√3
sin²Ф+cos²Ф+2sinФ×cosФ=3
2sinФ×cosФ=3-1=2
sinФ×cosФ=1 .....(eqn 1 )
tanФ+cotФ=sinФ/cosФ+cosФ/sinФ
=sin²Ф+cos²Ф/sinФcosФ=1/sinФcosФ
from Eqn 1
sin²Ф+cos²Ф+2sinФ×cosФ=3
2sinФ×cosФ=3-1=2
sinФ×cosФ=1 .....(eqn 1 )
tanФ+cotФ=sinФ/cosФ+cosФ/sinФ
=sin²Ф+cos²Ф/sinФcosФ=1/sinФcosФ
from Eqn 1
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