Question

Question 2 In the given figure find tan P − cot R

Class 10 - Math - Introduction to Trigonometry Page 181

Answer 1

Heya bhaiya here is your answer

using Pythagoras law we got

QR² = PR² - PQ²

=> QR = √ PR² - PQ²

=> QP = √ ( 13 )² - ( 12 )²

=> QP = √ 169 - 144

=> QP = √25

=> QP = 5


.°. tan P = QR/PQ

tan P = 5/12

and

Cot R = QR/PQ

Cot R = 5/12

now

tan P - Cot R

= 5/12 - 5/12

= 0

answer is nothing means 0 ! xD

===================================

Answer 2

Heya,

Here is the required solution:-

Using pythagoras theorem,

(PR) ² = (PQ)² + (PR)²

⇒(QR)² = (13)² - (12)

=169 – 144 = 25

 QR = 5 cm

tan p - cot r

= QR/PQ - QR/PQ

= 5/12 - 5/12

=0

Hope it helps u......