Question 1 In ΔABC right angled at B, AB = 24 cm, BC = 7 m. Determine (i) sin A, cos A (ii) sin C, cos C
Class 10 - Math - Introduction to Trigonometry Page 181
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angle A and B are complementary so sin and cos interchanges values..
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Given ,
AB = 24 cm
BC = 7 cm
now
from Pythagoras law
AC² = AB² + BC²
=> AC = √ AB² + BC²
=> AC = √ 24² + 7²
=> AC = √ 576 + 49
=> AC = √ 625
=> AC = 25
I )
.°. Sin A = BC/AC
Sin A = 7/25
.°. Cos A = AB/AC
Cos A = 24/25
ii )
.°.Sin C = AB/AC
SinC = 24/25
.°. Cos C = BC/AC
CosC = 7/25
====================================
AB = 24 cm
BC = 7 cm
now
from Pythagoras law
AC² = AB² + BC²
=> AC = √ AB² + BC²
=> AC = √ 24² + 7²
=> AC = √ 576 + 49
=> AC = √ 625
=> AC = 25
I )
.°. Sin A = BC/AC
Sin A = 7/25
.°. Cos A = AB/AC
Cos A = 24/25
ii )
.°.Sin C = AB/AC
SinC = 24/25
.°. Cos C = BC/AC
CosC = 7/25
====================================
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