Question

if sin theta = cos theta then 2tan^2 theta +sin^2 theta - 1 is equal to

Answer 1

Answer:

$\sin( \alpha ) = \cos( \alpha ) \\ \\ \alpha = 45 \\ \\ = > 2 { \tan }^{2} \alpha + { \sin}^{2} \alpha - 1 \\ \\ = > 2 \tan^{2}(45) + \sin^{2} 45 - 1 \\ \\ = > 2(1)^{2} × \frac{1}{ \sqrt{2} }^{2} - 1 \\ \\ = > 2 + \frac{1}{2} - 1 \\ \\ = > \frac{3}{2}$

Here's The Answer My Friend....