if sin theta + cosec theta = 10/3. find the value of sin square theta + cosec square theta
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Answer:
sinØ +cosecØ =2
sinØ + 1/sinØ =2
sinØ +1 = 2sinØ sin?Ø -2sinØ +1=0
(sinØ -1)? =0 sinØ = 1 hence,
coseco = 1 now, sinnø + cosecnØ = (1)" + (1)n =1 +1=2
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