Question

the first third and fourth terms of a proportion are 11 , 6 and 36 find the second term

Answer 1

AP=11,6,36
a=11
d=6-11
d=-5
a+(n-1)d
11+(n-1)-5=0
(n-1)-5=-11
(n-1)=-11/-5
n-1=11/5
n=11/5+1
n=16/5
a+(n-1)d
11+(2-1)-5=0
11-5=6
T2 =6