If sin theta + cosec Theta = 3(1/3) find the value of sin square theta + cosec square theta
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Answer:
Given sinθ+cosecθ=2
⟹sinθ+
sinθ
1
=2
squaring on both sides
(sinθ+
sinθ
1
)
2
=4
⟹sin
2
θ+
sin
2
θ
1
+2(sinθ)(
sinθ
1
)=4
⟹sin
2
θ+
sin
2
θ
1
+2=4
⟹sin
2
θ+
sin
2
θ
1
=2
⟹sin
2
θ+cosec
2
θ=2
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