Question

if sin theta equal to 1 by 3 then prove that Cos A into cosec A + tenA into secA equal to 16 root 2 + 3 upon 8​

Answer 1

Step-by-step explanation:

sinA = 1/3 , cosecA = 3

cosA = √1 - sin²A

= √(1 - 1/9) = √(8/9) = (2√2/3)

tanA = sinA/cosA

= (1/2√2)

secA = (3/2√2)

value of :-- cosA*cosecA + tanA*secA

(2√2/3) * 3 + (1/2√2)(3/2√2)

2√2 + 3/8

(16√2 + 3)/8