if sin theta equal to A upon B then find cos theta
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cos theta = √( B^2 - A^2) / B
hope you got it...
hope you got it...
rattanjha32:
Yeah i got it
Answered by
3
here
for ratio of sin, p=A,h=B
so,b become root (B^2 -A^2)
now,
cosθ=b÷h
=root(B^2-A^2)÷B
for ratio of sin, p=A,h=B
so,b become root (B^2 -A^2)
now,
cosθ=b÷h
=root(B^2-A^2)÷B
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