if sin theta is equals to 11 upon 61 find the value of cos theta using trigonometry identity please give me answer
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HEY MATE HERE IS YOUR ANSWER
sin theta = 11 /61
sin theta = P/H
from pythogoras theorem
H^2 = P^2 +B^2
(61)^2 = (11)^2 + B^2
(61)^2 -(11)^2 = B^2
(61+11)(61-11) = B^2
72×50 = B^2
3600= B^2
60 = B
Cos theta = B/ H
Cos theta = 60/61
sin theta = 11 /61
sin theta = P/H
from pythogoras theorem
H^2 = P^2 +B^2
(61)^2 = (11)^2 + B^2
(61)^2 -(11)^2 = B^2
(61+11)(61-11) = B^2
72×50 = B^2
3600= B^2
60 = B
Cos theta = B/ H
Cos theta = 60/61
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