if sin theta equals to 3/5 show that cos square theta minus sin square theta by cos theta equals to 1 minus tan squared theta by sec theta
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Let theta = x
sin x= -3/5 , 180° < x < 270°
cos x=×/-(1-sin^2x)^1/2 = +/-(1–9/25)^1/2
cos x = -4/5 (x lies in 3rd quadrant )
Now
tan x = sin x/cos x = (-3/5)÷(-4/5) = 3/4 .
sec x = 1/cos x = 1/(-4/5) = -(5/4) , Answer
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