Question

if sin theta equals to A/B then find the value of cos theta​

Answer 1

Answer:

√{B^2- A ^2}/B

Step-by-step explanation:

that's the answer mate

Answer 2

Sinθ=a/b

∴, cosθ=√(1-sin^2θ) [∵, sin^2θ+cos^2θ=1]

or, cosθ=√(1-A^2/B^2)

or, cosθ=√[(B^2-A^2)/B^2]

or, cosθ=√(B^2-A^2)/B^2