Question

If sin theta is 15/17,then find 15 cot theta+17 sin theta /8 tan theta+16 sec theta

Answer 1

Answer:

43

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Step-by-step explanation:

suppose you have a triangle

with the side is 15

and the incline part is 17

you will get the bottom part $\sqrt{17^2 - 15^2} = 8$

then cot theta = 1/tanθ , where tan is side/bottom = 15/8, which gives cot θ = 8/15

sin theta is 15/17

tan theta is 15/8

sec θ = 1/cosθ , where cos θ = bottom/incline = 8/17, which gives secθ=17/8

then,

15 cotθ + 17sinθ / 8tanθ +16 secθ = 15.(8/15) + 17.(15/17)/(8.(15/8)) + 16.(17/8)

=8+ 15/15 + 17.2

=8+1+34 = 43